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Question 1 of 6
1 of 6
$$a=\sqrt{{c^2}-b^2}$$ is a __________ of $$a^2+b^2=c^2$$.
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Rewriting $$a^2+b^2=c^2$$ to $$a=\sqrt{{c^2}-b^2}$$ makes $$a$$ the subject.