Lesson video

Hello and welcome to this lesson called "Scale Diagrams for Converging Lenses".

This is from the unit called Electromagnetic Waves, and my name is Mr. Norris.

So converging lenses are everywhere.

They're in magnifying glasses.

They're in cameras, okay? And there's a converging lens right here that I'm talking into right now.

However, these are not converging lenses.

Converging lenses fix longsight.

I'm shortsighted.

These glasses have a different kind of lens in them.

That's for another lesson.

But the question is, right, we know that converging lenses form a clear image, but how do you know how big the image is gonna form and where it's gonna form? Do you want a magnified image like this, that's better, or do you want a diminished, an inverted image like this? So it turns out you could draw a scale ray diagram of a lens that predicts the size and position of the image.

So that's what we're gonna do in this lesson.

The outcome of this lesson is that hopefully, by the end of the lesson, you'll be able to describe the uses of converging lenses and you'll be able to draw scale ray diagrams to determine the size and position of an image.

Here are some key words that will come up this lesson.

Object distance, image distance, principle focus, focal length, and principle axis.

All of these words will be explained as they come up in the lesson.

The lesson has two sections, and the first section we'll look at the uses of lenses to form images on a screen.

And in the second section, we'll look at how to draw these scale diagrams for converging lenses.

Let's get going with the first section.

So we know that a converging lens can focus light to produce an inverted image of an object on a screen.

So have a look at the diagram and you might have had the opportunity to do that using a converging lens yourself to produce an image of something outside the window on a screen.

And we know that the distance between the object and the lens is called the object distance.

And we also know that to produce a sharp, which means non-blurry image, the screen has to be placed at exactly the right distance from the lens for that object and that lens, and that's called the image distance.

And that can vary depending on the object distance and depending on the lens used.

If an object is distant, then the rays of light from that distant object that pass through the lens are effectively parallel.

So there's an object and if it's a very large distance away, then kind of that middle ray, we can think of all of the rays kind of around that middle ray are effectively hitting a very distant lens parallel coming from that point.

And parallel rays are focused to a point called the principle focus of the lens, which is labelled there.

The image that's produced is diminished and inverted like we saw in that first slide.

The focal length of a lens is the distance from the centre of the lens to the principle focus.

So that's that distance there.

Let's just check those terms, give the correct terms for labels X and Y, which is what we just went through.

Pause the video if you need to.

Okay, here are the answers.

So point X is called the principle focus of the lens.

And it's the principle focus 'cause it's where parallel rays of light are converged to.

If the rays of light instant on the lens are not parallel, then they'll meet as a focus, but it's not the principle focus unless the rays of light hitting the lens are parallel.

And Y is the focal length of the lens, the distance between the centre of the lens and the principle focus.

Well done if you've got both of those.

So the image distance, the point where rays of light will be converged to where you need to put a screen to get a clear image of the object, the other side of the lens, that image distance and the image size or magnification depend on two factors, the power of the lens and the object distance.

So the shorter the object distance, the greater the image distance and the greater the image size.

And that is a pattern that goes on until the object distance reaches the focal length or closer.

So this animation shows that.

We start with the distant object, which gets closer to the lens.

And you could see that image distance becomes greater as the object distance becomes shorter.

We can also see the image size increasing as the object distance decreases.

And that happens all the way till the object reaches the focal length or closer.

Because when the object is too close to the lens, i.

e.

at the focal length or closer, then no image can be formed on a screen.

So at the focal length is here, or closer is here.

Okay, and at those points, no image can be formed on a screen because the lens can't refract the rays enough to make them converge when the object's too close.

Because from closer objects, the rays are diverging, spreading out more, okay? The closer the object, so if the object is too close, the rays are too diverging and the lens can't refract the rays enough to make them actually come together and converge.

So the rays then leave the lens parallel or diverging and they never meet at a point because they're parallel or spreading apart, diverging.

So they never form a clear image or a focus.

Let's do a quick check about what we've just gone through.

Fill in the gaps on this slide.

Pause the video and have a go at working out what goes in each gap.

Off you go.

Right, I'll give you some feedback now.

As the object distance decreases towards the focal length, the image distance and the image size both increase.

The image goes from being diminished to being magnified, and the image is always inverted.

So here's the animation that shows that, again, as the object distance decreases, image distance and image size both increase.

The image goes from being diminished to being magnified.

Now it's magnified, but it started diminished, smaller than life size.

But the image is always inverted.

Let's look at a specific use of this kind of lens now.

So in a camera, a lens focuses lights onto a small light sensitive CCD, which stands for charge capture device, it's just the tiny light sensitive screen that detects the light and creates electrical signals which are sent to the digital camera or phone's memory to store the image as digital information.

In older style cameras, the CCD would've been photographic film.

So in a phone camera, and in fact, in all cameras, the CCD is very close to the lens.

Okay, we're talking perhaps like five millimetres between where the lens is and where the CCD is within the phone casing.

So when light is focused on the CCD, the object distance is far greater than the image distance for almost anything you photograph.

And phone cameras now have sometimes have very specialist, like separate lenses called macro lenses for photographing something that's very, very close to the phone because it needs to switch to a different lens.

Otherwise the normal lens for taking pictures of objects normal distances away won't be able to focus the light on the CCD successfully.

And the human eye works in a similar way to how cameras work.

But instead of a CCD or photographic film, the back of the eye is called the retina, which is covered in light-sensitive cells.

It's the screen where light ray must be focused to form an image.

And the depth of an eyeball is only about two centimetres.

So the retina is only about two centimetres behind the lens.

So again, like just like the cameras, the object distance for most objects we look at will be much greater than the image distance.

The image distance will only be about two centimetres.

And just like cameras, the image on the retina is inverted.

But with the human eye, our brain actually flips this image kind of in our mind so that we see things the right way up, even though the image that forms on the back of our eyes is upside down compared to how the objects are in real life.

And we know that moving an object closer to a lens will increase the image distance, okay? When you bring the object closer to a lens, that's gonna push the image further away.

But for a camera or the human eye, the image must always form in the same place, which is on the CCD or photographic film or on the retina, okay? So if an object's too close, then the razor too diverging, the image distance is too far, and the image on the CCD would be blurry.

So in cameras, adjustments can be made to the lens position to ensure that the image always forms on the CCD.

And cameras can also switch between multiple lenses, like I mentioned earlier.

And that'll make sure that the image always forms on the CCD.

A clear image always forms on the CCD.

Now the human eye does a similar job, but in a different way.

If an object's too close, then the image on the retina would be blurry 'cause the light from a closer object is too diverging.

Now in the human eye, the ciliary muscles, that's these, they actually change the power of the lens by kind of pulling it to change its shape to change the lens curvature.

And that changes the lens power so that light from closer objects can be focused on in the right place.

So keeping the image distance constant by changing the power of the lens.

Obviously with both cameras and the human eye, there is still a distance, which the lens cannot focus the image onto the right place.

So there is a minimum distance that objects have to be away for you to be able to focus them.

And if you bring your finger close to your eye, you'll notice there's a point where your eye can't focus on your finger anymore and it becomes blurry and you've reached that minimum distance.

Okay, here's a different use of this kind of lens.

A projector.

So in a projector, the object is actually a small bright screen behind the lens that's giving out light.

And then the lens focuses that light and it focuses on a projection screen, which is a large distance away.

Now with a projector, you want to create a much bigger image of whatever's on that small bright screen within the projector.

So how do you produce a magnified image on a screen? Well, the small bright screen must be placed between one and two focal lengths behind the lens so that the image distance is bigger than the object distance because the image needs to form on the screen, which is much further away from the lens than the small bright screen is.

And that also means you get a magnified image of whatever's on that small bright screen.

So you get a magnified inverted image on the projection screen.

And what that means is the small bright screen must display an inverted version of the image that you want to be projected so that when whatever's on the small bright screen is inverted, so it's projected on the screen, it then appears the correct way up that you want.

And this is how project classroom projectors work and also cinema projectors.

Let's do a check on what we just talked through.

Which diagram best represents a lens forming an image in a camera and the human eye and a projector? So which one, A or B, links with a camera and the human eye and which one links with a projector? Should be fairly quick to do, five seconds.

I'll give you some feedback now.

A links to a camera and the human eye because the image distance is much shorter than the object distance because the camera and the human eye have to focus the light on the CCD or photographic film or the retina at the back of the eye, which is only a very tiny distance from the lens.

So that's much more like A.

Whereas a projector is much more like B, where the object is a tiny screen a tiny distance from the lens and the lens of the projector then projects a magnified image onto a screen, which is a much further distance away from the lens than the object was.

So well done if you've got those the right way round.

Okay, time for a task now on the uses of lenses to form images on a screen.

So for each pair of statements, identify which applies to cameras and which applies to projectors.

So put C for cameras, P for projectors, both if the statement applies to both or neither if the statement applies to neither.

Pause the video now and have a go at that task.

Okay, I'll give you some feedback now.

So the object is a small bright screen placed between F and 2F, that is projectors.

And there's a minimum object distance, but no maximum.

That's cameras because lights can be.

The object can be as far away as you like because the further away light is, the rays will be parallel and they'll still be able to be projected on the camera's CCD.

But there is a minimum object distance because if the object is too close, then a camera can't focus it.

So well done if you've got those the right way around.

The image needs to form close to the lens, that's a camera.

The image needs to form much further from the lens, that's a projector.

And then the next set of statements basically say the same thing.

The object distance has to be bigger than the image distance basically in a camera.

And the object distance has to be much smaller than the image distance in a projector because the screen that you are projecting onto is much further away than the tiny screen that you are projecting in a projector.

The image is diminished in a camera and the image is magnified in a projector and the image is inverted in both and the image is upright in neither.

So well done if you got most of those right.

So that takes us to the second section of the lesson where we'll look at how we draw these scale ray diagrams for converging lenses to predict the position and size of the image that forms on the screen.

So to engineer an optical device like a camera or a projector, you need to know exactly where the image will form and what size it's gonna be, and this can be predicted by drawing a scaled ray diagram.

So the lens used can be represented using the correct symbol.

So here's a reminder that the symbol for a converging lens is that symbol there, and the symbol for a diverging lens is that symbol there.

So lights from the surroundings reflects in every direction from every point on the object, the tree in this case.

And many rays of light pass through the lens from each point.

So they're the rays of light that pass through the lens from that point on the object, and they're gonna be refracted to a point here by the lens on the screen.

And here are the rays of light that come from that point on the object.

And these are the ones that pass through the lens and they're gonna be refracted to a point here on the screen.

And these are the rays that reflect from this point on the object, and these are the ones that pass through the lens from that point, and they're gonna be refracted to a point here on the screen.

And here are the rays of light that come from that point on the object, and here are the ones from that point that go through the lens and they are going to be refracted to a point here on the screen.

So all of the rays that pass through the lens from the same point on the object meet at a single point, a set distance from the lens, the image distance, that's where you need to put the screen.

That's where I put the screen in this diagram.

And that creates a bright spot of light from that point on the object.

So the images created from the different bright spots made by all such trays from the different points on the object like this.

Let's do a check about how converging lenses form an image on a screen.

So Andeep creates an image on a screen using a converging lens, the top one that's pictured on the right of the screen there.

Andeep then swaps the lens for one with the same power, but half the diameter.

So the second lens down.

It's smaller, half the diameter.

And then Andeep swaps back to the original lens, but with half of the lens covered and no other conditions change.

So which statements are true about the three images Andeep creates with those three lenses? Take a moment to pause the video, read through each option and decide which statements are true about the three images created.

Pause the video now.

Have a go.

Right, I'm gonna give you some feedback now.

Okay, statement A, the focal length of the lens, it's always the same.

Well, that's true 'cause the lens is always the same power.

It says that in the question.

So the image distance and magnification is always the same.

Well, that's true because it's the same power of lens and the same object at the same object distance.

So that's true.

Statement B, the amount of light creating the image is always the same.

Now that's not gonna be true 'cause in the second lens with half a diameter, only half as many rays or less actually will go through that lens and be focused onto the screen than with the larger lens.

And with the third lens, which was half covered, only half as much light is gonna go through as the first lens.

So the image brightness won't always be the same because the amount of light creating the image is less when Andeep swaps to the smaller lens and the half covered lens.

So B was not true.

Well done if you worked that out.

And then statement C, lights can always pass through the lens from every point on the object to the screen.

That's true.

So the full image does appear in all three.

And that's a big misconception sometimes with lenses.

Sometimes pupils think that covering up half a lens means only half the image appears.

But that's not how lenses work because light can still pass through that half covered lens from every point in the object to the screen.

So the full image will appear in all three.

Now that was quite a difficult kind of test of your understanding of how lenses form images.

So extremely well done if you got all three of those right.

So to predict the image distance and the image size, you only have to draw two or three of those rays that form the image from a single point on the object.

So that's great because there's a huge number of rays that form the image, but we only have to draw two or three of them that simplifies our job massively.

So rays from every other point on the object, we know they're gonna meet at the same distance, the image distance.

That's why we only need to bother drawing two or three.

And in theory, it doesn't matter which point on the object you choose to draw the way the ray is from.

However, it's a good idea to choose the highest point on the object 'cause that's gonna lead to the highest point on the image, and so give you the clearest indication of the image size or the magnification.

And we should say that the object and the image are usually represented using arrows.

So instead of forming an image of a tree, we're gonna be forming an image of an arrow on the screen.

Okay, let's make sure we've got this set up properly.

Which of the following shows an object, a lens and the principle axis in the correct arrangement to form an image to the right of the lens? Pause video now and choose the right option.

Okay, I'll give you some feedback now.

The correct option that shows an object, so the arrow, a lens, the lens symbol, and the principle axis, which is the horizontal line in the correct arrangement to form an image to the right of the lens, it's arrangement B, okay? Arrangement A could form an image on the left of the lens 'cause light would come from the object through the lens.

C and D are drawn completely incorrectly because the principle axis should pass through the middle of the lens and the arrow should be.

The base of the arrow should be on the principal axis and pointing vertically upwards.

So here is the beginnings of a scale diagram.

It's done on graph paper and it's done to scale.

And I've put scales on the axes as well.

Scales might not be included in all examples of this kind of task, but I've included them.

So you're really clear that it's a scale diagram and everything's drawn to scale.

So this object has a height of 10 centimetres.

That's the green arrow.

It's 40 centimetres from the lens.

So look at the object distance on the horizontal axis and the focal length of the lens is 10 centimetres.

Now if that's not marked for you, you have to mark in the principle focus at the correct distance, which is the focal length.

So a little cross at 10 centimetres to show the position of the principle focus of this lens.

And then the rays that you need to draw.

Remember, we're only gonna draw two or three.

They're called the principle rays and here are the rules for drawing them.

So for the first principle ray, a ray that's parallel to the principle axis is refracted to the principle focus.

So parallel to the principle axis is refracted to the principle focus.

So it goes through the principle focus like that.

And that's just.

We know that parallel rays get refracted to the principle focus.

So that's just a rule that actually we knew already.

Okay, the second principle ray, a ray that passes through the centre of the lens, it turns out it's not refracted and that's all to do with the symmetry of a lens.

So you just draw it passing through centre of the lens and it's not refracted.

So straight through.

And actually that's enough to give the position of the image.

So we could draw it in there.

Okay, it looks like the image distance is 13 centimetres from the lens.

If you look at the image distance scale and the image height, it looks like it's about four boxes.

So the image height is four centimetres.

That's a diminished image smaller than the object is in real life.

Now you can draw the third principle ray, which is this, a ray arriving at the lens from the principle focus.

So that's from the principle focus on the left of the lens.

Can you see how it's drawn from the top of the arrow and goes through the principle focus that was on the left of the lens and then it hits the lens and that's gonna become parallel.

And you can see all three of those rays meet at the same point, which is the top of the image.

So you don't have to draw the third ray, but it can help you confirm that you've drawn the other two correctly if all three of the rays meet at the same point.

And in this case, we know that the image is inverted 'cause it's upside down.

The arrow is upside down compared to the object and it's diminished because it's smaller compared to the actual object size.

Okay, let's check you've got the idea of doing these ray diagrams. So make a quick copy of this diagram first and then add rays and the image to show what a ray diagram should look like.

Use a ruler to do this so it looks neat.

And your principle focus of the same distance in front of the lens and behind the lens, those two crosses.

But this doesn't need to be to scale.

So this is just getting the hang of what these diagrams should look like.

Pause video now and have a go at this check.

Right, I'll give you some feedback now.

So you should have just started by copying what's on the screen now.

And then you should have added the three principle rays for this kind of lens.

So a ray that's parallel to the principle axis is refracted through the principle focus, so it should look like that.

And then a ray that passes through the dead middle of the lens isn't refracted.

So use a ruler, just go straight through the middle of the lens, and then a ray that goes to the other principle focus and hits the lens doesn't change direction at any of those points.

It only changes direction at the lens when it's refracted.

So it becomes parallel.

So make sure that your diagram looks like that and it's worth spending two or three minutes.

Now pause the video to just practise drawing that out maybe two or three times just so you get the hang of and get the feel for how to draw those rays to predict where the image should be.

And of course you should have added the image in, and in this case, it's a diminished and inverted image.

So following that process, we'll find the location of the image for any object distance that will produce an image on the screen.

So any object distance from very, very far away up to the focal length will produce an image on the screen and you just follow that process and it will work.

So here's another example, but the object is now much closer to the lens.

It's only 15 centimetres from the same lens, so follow the same process.

Okay, a parallel ray is refracted through the principle focus.

A ray that goes through the centre of the lens is not refracted, that's actually enough to form the image.

But I'm gonna do the third ray anyway, which goes through the other focus and becomes parallel.

They should all meet, and that this time forms a magnified image, which is 28 centimetres from the lens reading the image distance scale there.

So this works to find the location of the image for any object distance that's gonna produce an image on a screen.

Let's do a check then, a final check before you do some of these yourself.

Match each principle A to the correct description of where it is refracted by this kind of lens.

Pause the video now and have a go at that task.

Okay, time for some feedback now.

So a ray parallel to the principle axis is refracted to pass through the principle focus.

The other side of the lens.

A ray that passes through the centre of the lens is not refracted, that's the easy one.

And that leaves a ray that arrives at the lens from the principle focus, that's refracted to become parallel.

Well done if you've got all three.

So for your task, I'm gonna give you three ray diagrams to do.

And these are really designed to be done on the sheet that goes with this lesson.

But if you don't have access to that, then you can just draw these diagrams yourself first on graph paper or squared paper, and then add the rays to your own versions of these diagrams. But do your best to try and make sure that they're drawn with a ruler, they're neat, and that they're drawn to scale because that's the point.

Otherwise the numbers won't work out.

So for the first ray diagram, you've got a 15 centimetre high object, that's the green arrow on the diagram, which is 25 centimetres from a lens of focal length, eight centimetres.

And don't forget to add on mark the principle focus in front of the lens and behind the lens at the distance in the question.

So that's the first ray diagram to do.

And the second one will be for a 12 centimetre high object, which is 30 centimetres from a lens of focal length, 15 centimetres.

And then the third radio diagram that I'd like you to do is for an object that's six centimetres high, 21 centimetres from a lens of focal length, 15 centimetres.

So have a go at those three, draw the diagrams. Don't forget to also record the image distance and describe the nature of the image.

Is it upright or inverted? And is it magnified or diminished for each diagram? You should pause the video now and give that task a good go.

If you're working from the video, then you might need to pause the video and go back a couple of slides to do the questions, question one and question two.

And then there's obviously question three on this slide as well.

So pause the video now.

Off you go.

Right, I'll give you some feedback now.

Let's see how you got on.

So for the first one, which was a 15 centimetre high object, 25 centimetre from a lens focal length, eight centimetres.

The first ray is parallel and that should be refracted through the principle focus.

The second principle ray goes straight through the centre of the lens.

That's the easy one.

And then that might be enough to draw in the image, but it's always a good idea to draw the third ray, which goes through the other focus on the left of the lens.

And that becomes parallel.

And that should allow you to draw an image with confidence.

And that image is inverted, it's upside down and diminished.

It's smaller than the original object.

And the image distance is 12 centimetres.

And you should be able to get to within one centimetre of that by drawing an accurate diagram.

Here's the second ray diagram I asked you to draw.

Again, a ray that's parallel is refracted through the principle focus.

There's a ray that goes straight through the centre of the lens, that's the easy one.

And then the third ray goes through the other principle focus on the left of the lens and becomes parallel.

And that allows you to draw in an image.

And in this case, the image is not magnified or diminished, it's the same size as the object.

And you might have been able to predict that because you might have spotted in advance that the object has been placed at double the focal length distance.

The focal length is 15 centimetres and this object is at double the focal length, 30 centimetres, and that is the special distance where the object is neither diminished, where the image is neither diminished nor magnified.

It's life size.

So it's inverted and life size.

And the image distance is at 30 centimetres, which is the same as the object distance because that's another property of that special distance of double the focal length.

Here's the third ray diagram I wanted you to draw.

So a ray that's parallel is refracted through the principle focus.

A ray that goes through the centre of the lens isn't refracted.

And then you've got a final a ray that goes through the other principle focus and becomes parallel, and you can draw in the image and hopefully you've got something like that.

The image is inverted, but it's magnified this time, so it's bigger than the original object size.

And the image occurs at an image distance of 50 centimetres.

Well done if you got that.

Here's a summary of the lesson.

In cameras and the human eye, a converging lens needs to focus the image on the CCD or retina, and the object distance will be much bigger than the image distance, so the image ends up diminished and inverted.

Whereas in a projector, the image needs to be focused on the projection screen.

The object distance is much smaller than the image distance.

Image distance is much bigger, so the image is magnified and inverted.

And we've just seen how the image distance and height can be predicted by drawing a scale ray diagram from a single point on the object.