When we compare lists of factors of two or more numbers, any factors that are the same are the common factors.

The distributive law says that multiplying a number by a group of numbers added together is the same as doing each multiplication separately.

Use knowledge of the distributive law to solve further two-part problems

Maths

In this unit pupils will use knowledge of distributive law to calculate products beyond known times tables facts In the future unit pupils will explain the relationship between multiplying a number by 10 and multiples of 10 They will explain why a zero can be placed after the final digit when multiplying it by 10 and why the final digit zero can be removed from a multiple of 10 when dividing by 10

In the prior unit pupils explained how each part of a multiplication and division equation related to a story. They partitioned one of the factors in a multiplication equation in different ways using representations. In this unit pupils will use knowledge of distributive law to calculate products beyond known times tables facts.

Apply the distributive law to multiplication

What is the common factor of the two multiplication expressions being added together in this equation? 6 × 5 − 4 × 5

Match the expressions that have equal value.

Solve this equation using the distributive law. 8 × 4 − 3 × 4 = {{ }}

Solve this equation using the distributive law. 7 × 5 − 2 × 5 = {{ }

There are 10 boxes of 6 eggs on the shelf. 4 boxes fall off and the eggs inside all break. How many eggs are left on the shelf? {{ }} eggs

Aisha gets £8 pocket money each week but chooses to spend only £3 of it and save the rest. How much will she save after 8 weeks? £{{ }}

Which of the numbers in the following equation is the product? 18 = 6 × 3

Which of the following expressions represents the total number of apples if I have 3 bags of 7 apples and 3 bags of 5 apples.

Which of the following expressions is the array representing?

This lesson will be removed by end of Summer Term 2025.

Use knowledge of the distributive law to solve further two-part problems

Lesson outcome

This lesson will be removed by end of Summer Term 2025.