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Question 1 of 6
1
of 6
In which of these is $$a$$ the subject?
Select one answer
$${1\over a}=bc + 2$$
$$a = {bc+2 \over 4a}$$
$$a^2 = bc + 2$$
$$a={5b-2\over 2c+3b}$$
$${1\over 3}a = b^2+c + 2$$
For $$a$$ to be the subject it must be expressed in terms of other variables (not including $$a$$ itself) and have an exponent of 1 and a coefficient of 1.
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