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Question 1 of 6
1
of 6
What is the simplest form of the fraction $$18x^2y^6\over 12x^5y^2$$?
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$$3y^3\over 4x$$
$${3\over 2}x^3y^4$$
$${3y^4\over 2x^3}$$
$${3xy^5\over 2x^4y}$$
$${9xy^3\over 6x^3}$$
The highest common factor of$$18x^2y^6$$ and $$12x^5y^2$$ is $$6x^2y^2$$
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