The reciprocal is the multiplicative inverse of any non-zero number.

Solving simple linear equations with a multiplicative step

Maths

In this unit, pupils learn how to rearrange an equation to find a specific value that satisfies the equation. In expressions and formulae, pupils use their understanding of rearrangement to change the subject of a formula.

In the prior unit, pupils saw that an arithmetic sequence can be represented graphically and that this is a linear relationship. Any point on the line satisfies this relationship. In this unit, pupils learn how to find a value that satisfies the relationship when the second value is known, without the aid of the graph.

Solving linear equations

Using this bar model, the solution to the equation $$6x = 30$$ is when $$x= $${{}}

Using this bar model, the solution to the equation $${1\over 4}x = 8$$ is when $$x=$$ {{}}

The solution to $$3x = 396$$ is when $$x=$$ {{}}

Which of these show the correct working to isolate one positive $$x$$ for the equation $$0.5x = 3.5$$?

The solution to $$-9x = 36$$ is when $$x =$$ {{}}

Which of these is the solution to $${4\over 5} x = 20$$?

Which of these equations can be written from this bar model?

The solution to the equation $$x + 3 = 17$$ is when $$x$$ = {{}}

The solution to the equation $$x − 8.6 = 10$$ is when $$x$$ = {{}}

Any non-zero number multiplied by its reciprocal is equal to {{}}

Match each calculation to an equivalent calculation.

This lesson will soon be taken down.

Solving simple linear equations with a multiplicative step

Lesson outcome