New
New
Year 10
Edexcel
Higher

Limiting reactants

I can identify a reactant as being in excess or the limiting reactant and use that information to calculate a theoretical yield.

New
New
Year 10
Edexcel
Higher

Limiting reactants

I can identify a reactant as being in excess or the limiting reactant and use that information to calculate a theoretical yield.

warning

These resources will be removed by end of Summer Term 2025.

Switch to our new teaching resources now - designed by teachers and leading subject experts, and tested in classrooms.

Lesson details

Key learning points

  1. In a chemical reaction, the atoms in reactants are rearranged and are the same atoms that are in the products.
  2. A theoretical yield is calculated using the stoichiometry of a balanced equation & relevant mathematical relationships.
  3. The number of moles of limiting reactant available is used to calculate the theoretical yield of a reaction.
  4. If a reactant is added in excess, not all of it will react and some will be found in the final product mixture.
  5. A limiting reactant is one that restricts the amount of product that can form from the available particles.

Keywords

  • Limiting reactant - The reactant that completely reacts, thereby determining the maximum amount of product that can be formed in a chemical reaction. All other reactants will be present in excess.

  • Excess reactant - Any reactant present in a greater amount than is necessary to completely react with the limiting reactant.

  • Theoretical yield - The maximum calculated mass of product expected to form from a given amount of reactants.

  • Mole - A mole of a substance contains 6.02 × 10²³ particles of it. The mass of one mole of a substance is its relative mass in grams.

  • Stoichiometry - The molar ratio of the reactants to the products in a chemical reaction.

Common misconception

Pupils sometimes fail to understand that excess reactant particles remain in the reaction mixture after the reaction.

Provide a balanced equation and challenge pupils to draw diagrams of a final mixture, stressing that excess particles would also be present. Challenge pupils to consider how the product could be extracted from the excess particles.

Demonstrate the reaction of magnesium & oxygen – a great opportunity to revisit skills relevant to equipment choice, practical technique & relevant measurements. Challenge pupils to use the mass of product formed to determine the mass of O₂ that reacted, then determine if the Mg or O₂ was limiting.
Teacher tip

Equipment

2 cm strip of Mg crucible + lid balance tongs heatproof mat, Bunsen burner, tripod clay triangle

Content guidance

  • Risk assessment required - equipment

Supervision

Adult supervision required

Licence

This content is © Oak National Academy Limited (2024), licensed on Open Government Licence version 3.0 except where otherwise stated. See Oak's terms & conditions (Collection 2).

Lesson video

Loading...

6 Questions

Q1.
Match the following terms to the correct definition.
Correct Answer:relative atomic mass,the average mass of the atoms of an element compared to carbon-12

the average mass of the atoms of an element compared to carbon-12

Correct Answer:relative formula mass,the sum of the relative atomic masses of all the atoms in a formula

the sum of the relative atomic masses of all the atoms in a formula

Correct Answer:Avogadro's constant,the number of particles in one mole of a substance

the number of particles in one mole of a substance

Q2.
The formula for ammonium nitrate is NH₄NO₃. Which of the following ratios are correct?
Correct answer: The ratio of nitrogen to oxygen is 2 : 3.
Correct answer: The ratio of nitrogen to hydrogen is 1 : 2.
Correct answer: The ratio of oxygen to hydrogen is 3 : 4.
The ratio of oxygen to nitrogen is 2 : 3.
Q3.
Chemical equations represent how the atoms in the rearrange to form the products.
Correct Answer: reactants, reactant
Q4.
Which of the following is the equation which links mass, relative formula mass and amount of substance?
Correct answer: mass = amount of substance × relative formula mass
mass = amount of substance ÷ relative formula mass
amount of substance = relative formula mass × mass
amount of substance = relative formula mass ÷ mass
Q5.
True of false? The following equation is balanced: C₂H₄ + 2O₂ → 2CO₂ + 2H₂O.
true
Correct answer: false
Q6.
Calculate the relative formula mass for calcium carbonate, CaCO₃. Relative atomic masses: Ca = 40; C = 12; O = 16.
Correct Answer: 100, one hundred, a hundred

6 Questions

Q1.
Match the following key terms to the correct definitions.
Correct Answer:limiting reactant,the reactant that completely reacts during a reaction

the reactant that completely reacts during a reaction

Correct Answer:excess reactant,a reactant that is left over at the end of the reaction

a reactant that is left over at the end of the reaction

Correct Answer:theoretical yield ,the maximum calculated mass of product expected from a reaction

the maximum calculated mass of product expected from a reaction

Correct Answer:mole,the unit for amount of substance

the unit for amount of substance

Q2.
Which of these statements about the equation are true? 2H₂ + O₂ → 2H₂O.
One mole of hydrogen reacts with one mole of oxygen.
Correct answer: One mole of oxygen reacts with two moles of hydrogen.
Correct answer: Two moles of water are formed for every two moles of hydrogen reacted.
Two moles of oxygen are needed to form two moles of water.
Q3.
True or false? In a chemical reaction there are the same number of atoms in the products as there were in the reactants.
Correct answer: true
false
Q4.
A student oxidises magnesium in a Bunsen burner flame. The oxygen is in excess. 2Mg + O₂ → 2MgO. How many moles of magnesium oxide would form from eight moles of magnesium?
Correct Answer: 8, eight
Q5.
Which is the limiting reactant if 6 moles of methane reacts with 4 moles of oxygen? CH₄ + 2O₂ → CO₂ + 2H₂O.
methane
Correct answer: oxygen
carbon dioxide
water
Q6.
A student oxidises 2.0 g of magnesium in a Bunsen burner flame. The oxygen is in excess. 2Mg + O₂ → 2MgO. What mass of magnesium oxide would form from 2.0 g of magnesium? Give your answer to 2 s.f.
Correct Answer: 3.3, 3.3 g, 3.3g