Changing the subject with more complex formula
I can apply an understanding of inverse operations to a complex formula in order to make a specific variable the subject.
Changing the subject with more complex formula
I can apply an understanding of inverse operations to a complex formula in order to make a specific variable the subject.
Lesson details
Key learning points
- With more complex formula, it is important to apply the inverse operations in the right order.
- The subject can be thought of as the unknown you are trying to find the value of.
- Instead of finding a value though, you will find an expression that the unknown is equal to.
Common misconception
The subject of a formula is just the first term in the formula.
Draw attention to the variety of equations and formulae used in the lesson.
Keywords
Subject of an equation/formula - The subject of an equation/a formula is a variable that is expressed in terms of other variables. It should have an exponent of 1 and a coefficient of 1.
Licence
This content is © Oak National Academy Limited (2024), licensed on Open Government Licence version 3.0 except where otherwise stated. See Oak's terms & conditions (Collection 2).
Video
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Starter quiz
6 Questions
$$5d+2$$ -
$$d \text{ }$$ multiplied by $$5$$ then add $$2$$
$${d\over5}+2$$ -
$$d\text{ }$$ divided by $$5$$ then add $$2$$
$${{d+5}\over2}$$ -
$$d\text{ }$$ add $$5$$ then divided by $$2$$
$$2d+5$$ -
$$d\text{ }$$ multiplied by $$2$$ then add $$5$$
$$5(d+2)$$ -
$$d\text{ }$$ add $$2$$ then multiplied by $$5$$
$${1\over5}(d+2)$$ -
$$d\text{ }$$ add $$2$$ then divided by $$5$$
Exit quiz
6 Questions
$${{d+6}\over8}=e$$ -
$$d=8e-6$$
$$8d+6=e$$ -
$${{e-6}\over8}=d$$
$${{d-6}\over8}=e$$ -
$$d=8e+6$$
$$8(d+6)=e$$ -
$${e\over8}-6=d$$
$${d\over8}-6=e$$ -
$$d=8(e+6)$$
$$2x=\sqrt{y}$$ -
$$x={\sqrt{y}\over2}$$
$$2\sqrt{x}=y$$ -
$$x=({y\over2})^2$$
$$\sqrt{2x}=y$$ -
$$x={y^2\over2}$$
$$2x^2=y$$ -
$$x=\sqrt{y\over2}$$
$$(2x)^2=y$$ -
$$x={{\sqrt{y}}\over2}$$